修改为指定值
DO $$DECLARE r record; BEGIN FOR r IN SELECT sequence_name FROM information_schema."sequences" LOOP EXECUTE 'ALTER SEQUENCE '|| r.sequence_name ||' restart WITH 10000'; END LOOP; END$$;
根据表的id修改
DO $$ DECLARE r record; start_value integer := 0; BEGIN FOR r IN SELECT tablename||'_id_seq' AS sequence_name, tablename FROM pg_tables WHERE schemaname = 'public' LOOP EXECUTE 'SELECT max(id)+1 AS max_value FROM ' || r.tablename INTO start_value; IF start_value IS NULL THEN start_value:= 1; END IF; RAISE NOTICE 'start_value % %', r.tablename,start_value; EXECUTE 'ALTER SEQUENCE '|| r.sequence_name ||' restart WITH ' || start_value; END LOOP; END$$;
补充：postgresql 13 数据库 sequence 的 maxvalue 最大值是多少"htmlcode">
那就需要查看下 bigint 的值 以上为个人经验，希望能给大家一个参考，也希望大家多多支持。如有错误或未考虑完全的地方，望不吝赐教。
# cat /etc/centos-release
CentOS Linux release 7.8.2003 (Core)
# su - postgres
Last login: Thu Oct 15 09:59:33 CST 2020 on pts/1
ppostgres@nodepg13-> psql -c "select version();"
version
---------------------------------------------------------------------------------------------------------
PostgreSQL 13.0 on x86_64-pc-linux-gnu, compiled by gcc (GCC) 4.8.5 20150623 (Red Hat 4.8.5-39), 64-bit
(1 row)
create sequence
$ psql
postgres=# create sequence seq_1;
CREATE SEQUENCE
postgres=# select c.relname,c.relkind,s.* from pg_class c,pg_sequence s where c.oid=s.seqrelid;
relname | relkind | seqrelid | seqtypid | seqstart | seqincrement | seqmax | seqmin | seqcache | seqcycle
---------+---------+----------+----------+----------+--------------+---------------------+--------+----------+----------
seq_1 | S | 40968 | 20 | 1 | 1 | 9223372036854775807 | 1 | 1 | f
(1 row)
seqmax = 9223372036854775807
maxvalue
NO MAXVALUE
The optional clause MAXVALUE maxvalue determines the maximum value for the sequence. If this clause is not supplied or NO MAXVALUE is specified, then default values will be used. The default for an ascending sequence is the maximum value of the data type. The default for a descending sequence is -1.
免责声明：本站文章均来自网站采集或用户投稿，网站不提供任何软件下载或自行开发的软件！ 如有用户或公司发现本站内容信息存在侵权行为，请邮件告知！ 858582#qq.com