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本文主要关于python的正则表达式的符号与方法。
findall: 找寻所有匹配,返回所有组合的列表
search: 找寻第一个匹配并返回
sub: 替换符合规律的内容,并返回替换后的内容
.:匹配除了换行符以外的任意字符
a = 'xy123' b = re.findall('x...',a) print(b) # ['xy12']
*:匹配前一个字符0次或者无限次
a = 'xyxy123' b = re.findall('x*',a) print(b) # ['x', '', 'x', '', '', '', '', '']
"htmlcode">
a = 'xy123' b = re.findall('x"htmlcode">b = re.findall('xx.*xx',secret_code) print(b) # ['xxIxxfasdjifja134xxlovexx23345sdfxxyouxx'].*"htmlcode">
c = re.findall('xx.*"htmlcode">d = re.findall('xx(.*"htmlcode">s = '''sdfxxhello xxfsdfxxworldxxasdf''' d = re.findall('xx(.*"htmlcode">s2 = 'asdfxxIxx123xxlovexxdfd' f = re.search('xx(.*"htmlcode">s = '123rrrrr123' output = re.sub('123(.*"htmlcode">import re def multiply(m): # Convert group 0 to an integer. v = m.group(0) print(v) # Multiply integer by 2. # ... Convert back into string and return it. print('basic/'+v) return 'basic/'+v结果如下
>autoencoder.png basic/autoencoder.png RNN.png basic/RNN.png rnn_step_forward.png basic/rnn_step_forward.png rnns.png basic/rnns.png rnn_cell_backprop.png basic/rnn_cell_backprop.png LSTM.png basic/LSTM.png LSTM_rnn.png basic/LSTM_rnn.png attn_mechanism.png basic/attn_mechanism.png attn_model.png basic/attn_model.png仿照上面案例,我们可以方便的对我们的任务进行定制。
subn相比sub,subn返回元组,第二个元素表示替换发生的次数:
import re def add(m): # Convert. v = int(m.group(0)) # Add 2. return str(v + 1) # Call re.subn. result = re.subn("\d+", add, "1 2 3 4 5") print("Result string:", result[0]) print("Number of substitutions:", result[1]) > Result string: 11 21 31 41 51 Number of substitutions: 5铁雪资源网 Design By www.gsvan.com广告合作:本站广告合作请联系QQ:858582 申请时备注:广告合作(否则不回)
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